So you have a VV or a VW device, and you want to make vaporz?

With variable devices hitting the market more and more regularly, you'll still see people wanting to sub ohm on them all, and the common question that's being tossed around is this;

"what's the lowest resistance it can run"

Before that question gets answered, ask yourself these questions....are you using a mechanical mod? Are you using a Variable Voltage mod? and finally, Are you using a Variable Wattage mod?

Those are three key questions to determining vaporz production on any device.

WHY? Simple fact, two of those three items can produce vaporz easily with subohm, while one of those three devices shine with higher resistance, NON subohm.

They key to any vaporz production is the end result, which is wattage. Wattage is that determining factor for heat. Face it, the more wattage you have the more vaporz you can produce. Wattage is also the calculation of a few key factors. Voltage, resistance and Current [break your calculators out, math is about to smack you in the face again]

Ohms law is the first thing you must know.

E [energy/voltage] = I [current/amperage] x Resistance [ohms]

From there you can use basic algebra to calculate the rest if you only have two figures to the equation.

Next is WATTS law.

P [watts/power = E [Voltage/Energy] x I [Current/Amperage]

Now, since that's out the way, lets move onwards.

A common misconception of mech mod transition users who are switching over to a wattage device, is to create the lowest resistance they can to produce as much vaporz as they possibly can. Reason being? A lower resistance, coupled with a standard voltage supply will create the heat, and the over all power they demand. And this is the farthest from the truth as possible.

A variable wattage device will simply take some key factors of your finished product to calculate the necessary voltage needed to produce that end result heat.

So lets look at some figures here

Majority of subohm vapers out there are using wraps that meter out at .2 [we'll use this figure, because it's easy to calculate on] Couple that with a fully charged high amperage batter of 4.2 and you'll get roughly 21 amps of current heating up that .2 ohm coil.

E [4.2volts] = [unknown] x .2ohms therefor 4.2volts / .2 ohms = 21amps

From that we can calculate the wattage

P [wattage] = 21amps x 4.2volts

P = 88.2 watts et voila.

With that being said, if you were to use a Variable voltage device then YES, having the lowest resistance will net you the highest possible wattage so to get you the most amount of vaporz!

With that out of the way, lets look at a variable wattage device. Every single variable wattage device will provide you two range of numbers, first being the obvious, the wattage range. Where the second is often overlooked, and that is the Voltage range.

Why is the voltage range important? Well it's massively important because without that voltage boosting on the chipset, it will not be able to provide to you the necessary voltage demanded to give you the wattage setting you're after.

When using a Variable wattage device, low resistances will actually be a NEGATIVE effect on vaporz production. And this is because you're not allowing the voltage boosting effect on the chip to do any work.

You want to aim for a higher resistance on the load, so to allow this chipset to do it's work, to provide to you more vaporz and to net you the result you're after.

Lets go back to math shall we? As we will use a standard of 20 watts as our setting.

If we were to use a .5 ohm load/coil [simple because most VW devices will fire that low] lets do some reverse calculation......

Since we only have two known factors, wattage demanded, and resistance/load we have to do further calculations to figure out the voltage supplied.

Another formula for calculating wattage is

W = E squared[voltage/energy] / resistance

20w = E squared / .5ohm (back to some basic algebra)

E Squared = .5ohms x 20w

E squared = 10 (to get the value of E, we must now calculate the root of 10)

E = (root 10) 3.1622

Long and drawn out, but you'll see that 3.16 volts is putrid, and pathetic. Why would anyone want to vape at just a hair over 3 volts? might as well stick to a ego device....the results are better right?

Remember when I said that higher resistances are better on VW devices? Well lets work out what a 1.5ohm load would net in regards to voltage required at 20 watts

20w = E Squared / 1.5ohm

E Squared = 1.5ohm X 20W

E Squared = 30

E = (root 30) 5.47

5.47volts. with a 1.5 ohm coil, that gets you 20 watts. No only is the vaporz much more abundant, you'll get better flavor, and you'll also (usually) get more throat hit and over all a much more satisfying vape.

Now you don't have to take my word for it, just trust the numbers.....

and just remember, Variable voltage devices [including straight mechanicals] like lower resistances for higher heat/wattage, where as Variable wattage devices like higher resistance for increase voltage output.

PS: If you don't like to do math, here are some quick links you can use for easy calculations.

Ohms Law Calculator: http://www.ohmslawcalculator.com/ohm...calculator.php